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What up? Everybody? Welcome to
another episode and let's ask Paul the podcast

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where I, Paul Abernathy, do
my best to answer all of your pressing

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electrical code related questions or anything related
to electricity or the National Electrical Code,

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or the secrets of life and all
that kind of good stuff. If you

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want to take part in it,
all you gotta do is go to Paul

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Abernathy dot com. It's free,
it's sponsored by Wicks, doesn't cost you

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anything, and it's a portal that
was put up a couple of years ago

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to allow me to be able to
address questions that people have. And it's

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kind of evolved because originally everybody knows
my love hate relationship with social media.

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And when you have that love hate
relationship with social media, you start to

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notice that you got to be there. You have to be there, it's

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just part of business. But then
you look at all the comments and you

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realize that people just struggle. And
the problem with social media is that everybody

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seems to think it's gospel and they
listen to it, and people start propagating

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misinformation, falsehoods, and it's kind
of like that thing you'll met, that

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little exercise where you get about ten
people together and you whisper something in one

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of them's ear, and then they
share with the next person, and the

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next person and the next, and
by the time it gets to the end,

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the story is totally different. That
reminds me of social media, okay,

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And the problem with it is some
people believe something so passionately that even

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if they're wrong, they're going to
argue it until they're blue in the face.

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And that's never a good thing for
education. So while I believe that

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social media can be an important tool
when it comes to education, it can

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also be detrimental to proper education,
spreading valid information, that type of thing.

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So I had to take it in
with the moderation and realize that it's,

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you know, consider the source.
You know, consider the source when

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you're when you're doing this social media
shopping when it comes to knowledge. Okay.

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Okay, So, as you've probably
guessed by the title of this episode,

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on this Let's ask Paul, somebody
asked me to talk about finding amp

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fridge ratings and the different ways that
we can find amps for something and how

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we might do this. Okay,
So I figured I would kind of do

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that and kind of break things down
the best I can to help people understand.

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How would I, you know,
calculate some of the things to find

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ampriage ratings depending on the question or
what's presented. Okay, so that's what

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you're in store for today on this
episode. And so I'm going to be

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spitting out some formulas. Okay,
that's right. We're going to be spinning

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out some formulas that you can pause
and jot down if you want, or

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you can just listen to them and
that type of thing. And so we

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will be coming out with a pocket
card that has all of this information on

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it, and we currently have one
available for voltage drop, so make sure

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you go check that out over on
our website fasttracksystem dot com. That's f

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A S T t R A X
S Y S T E M, so

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exactly how it sounds fast tracks with
t r X system dot com. And

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if you go there, you go
to our store, you'll see that we

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have the voltage drop cards. They're
pretty neat and even on the other side,

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I show you how they actually come
up with the K value that you

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use in your equation, so I
kind of show you how to do that,

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but I also give you the formulas
and things like that. So it's

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a nifty little card to have in
your wallet because you know, voltage drop.

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Even though it's not a mandated requirement
by the ANC except for sensitive electronic

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equipment or fire pumps, it's talked
about a lot and it can have a

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negative impact on the efficiency of your
circuit and the things that are plugged into

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that circuit. So it is definitely
something to be taken into consideration, and

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most engineers do. Most people I
know do, even if it's not a

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mandatory requirement by the ANYCA for again, anything other than sensitive electronic equipment or

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fire pumps. Okay, so other
than that, it's purely optional. But

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again it is something that people tend
to take into consideration, and it can

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affect the efficiency of whatever the load
is because certain equipment like to run between

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a certain voltage range, and if
your voltage drops out of that, then

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it's going to be any fission prematurely
cause the product to possibly fail. So

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things like that have to be taken
into consideration. All right, let's talk

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about single phase. When we're talking
about finding the amperage values on a single

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phase given a couple things. So
if I happen to know what the watts

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are, the volts are, and
I happen to know what the power factor

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is for a specific single phase load, and I'll give you an example.

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And in an exam type of question, they're probably going to give you all

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of these values, and if you
don't know what the power factor is,

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then you go to unity. You
can do one point zero zero if you

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want. But if they give you
a power factor, then obviously when we're

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dealing with amperags, we want to
take that power factor into consideration. If

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they're giving you that type of question, that has power factor in it,

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right, So let's look at the
first one. So if we know what

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the watts are of the load,
the formula is P over E times PF,

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PF being power factor, E being
voltage and peving the wattage power.

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So if I gave you a question
and it was one hundred and fifty watt

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load, and I told you that
there was a power factor of eighty six

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percent or point eight six, if
we work it into a decimal, go

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from the right side of the six
move two spaces to the left point eighty

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six. Always try to put percentages
into decimals when you're doing your math.

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It's a should be common knowledge by
now, but just remember to do that.

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And then, of course we give
you the actual voltage, which is

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two thirty volts. Again, folks, just to remind you, use the

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values they give you in the equation. If you're doing an exam, if

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they tell you it's two thirty volts, and you're in your mind thinking,

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well, wait a minute, this
is a two forty volt circuit. No

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use what they give you, okay, Use what they give you, okay.

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So in this case, it would
be one hundred fifteen hundred watts divided

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by e, which is the voltage
times the power factor. So the first

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thing you want to do is always
work the multiplication out first the lower part,

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So two thirty times point eight six. So I'm going to work it

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with you. So two thirty times
zero point eighty six, and that gives

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us one ninety seven point eight.
So now it's fifteen hundred divided by one

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ninety seven point eight. So fifteen
hundred divided by one ninety seven point eight,

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that's going to give me seven point
five eight. Three. Drop the

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three, so it's seven point five
eight is the amps? Okay? That

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is the actual amps that is the
current that we have for this equation,

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okay, and that took power factor
into the equation. Now, interesting is

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if power factor wasn't in the value, then it would be fifteen hundred divided

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by two thirty and that would be
six point five two. Okay, So

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it's uh, you know, the
power factor is making it not as efficient.

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So the current went up, but
if you take that out, that

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can be a different that's a difference
of about one amp, believe it or

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not due to that power factor.
Okay, So you want to make sure

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you're using whatever they give you.
Definitely want to use what they give you,

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all right, So let's see here. So that would be an example

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when we know the WHTT is the
voltage and the power and a power factor

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if it's available for the question.
So the next thing you might get a

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question it says, what if I
want to know what the answer are and

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I've got a load with a motor
it's a horse power, but I don't

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know how to figure it out.
Then they give you a power factor,

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they give you an efficiency and you're
like, okay, well it tells me

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that it's an efficiency rating of ninety
two percent, and it tells me,

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it's a power factor of eighty okay, and you may get this from the

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name plate of a motor. It's
single phase and it tells me it's one

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hundred and fifty volt motor, and
it's telling me that it is a half

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horse power half horse power. Okay. So immediately what some people would do

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is they would run to the back
of the of motors and go to the

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FLC. But that's not what you
do here, Okay, that is not

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what you do in this scenario.
The equation is, now you do do

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that when you're sizing for motors for
short circuit ground fall protection, when you're

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sizing for the conductors. All we're
doing here is finding the amps based on

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a question where it asks you specifically
to find the amps based on working this

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out. Okay. Now, interesting
enough, this is probably going to be

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further in lined with what's on the
name plate versus what's within the FLC because

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the name plates typically take things like
efficiency and power factor into the equation.

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So this is going to probably harmonize
more with what you would see on a

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name plate rather what you would see
in an FLC, which is in four

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thirty nine two fifty. Just remember
the FLC is what you're going to use

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in the code when you're sizing brand
circuits, feeders from motors and motors,

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short circuit ground protection, things like
that. And when you're doing the overload,

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you're going to use a nameplate.
So all I'm showing you is if

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they ask you a simple question and
want to know, what is the AMP

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load for a single phase half horsepower
one hundred and fifteen volt motor that has

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an efficiency rating of ninety two percent
and a power factor of eighty, how

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do you work it? Well?
This formula which I encourage you to jot

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this down in your codebook if you
have the If you're not preparing for an

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exam, you can write any damn
thing you want in your book. If

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you're preparing for an exam, be
careful make sure that they allow you to

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write in your codebook. And how
do you determine that? Then you've got

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to go to the test center.
Maybe they have a bulletin that you can

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look at, like PSI, if
that's who's doing your testing. They will

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have what's called a guide in a
bulletin, and it'll tell you what you

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can and what you can't do.
That type of thing, So just be

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aware of that. And in your
codebook if you can write in your codebook,

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like for example Texas, you can
jot things in your code book if

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you want. The best place to
do this is up near the front where

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the code panel members are because there's
usually a lot of blank spaces up there

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or a lot of room to write
stuff, and so it makes it nice

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to be able to jot your formulas, your owns low wheels, you know,

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example of a parallel series circuit,
all those type of things, all

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the formulas. That's a great place
to do it. But again, don't

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say Paul told you to do it. You get in trouble. You need

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to know whether or not you can
mark in your codebook, and you're going

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to have to check with the bulletin
or your test center wherever you're at in

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the country. So here's the formula. So the formula is horsepower times seven

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forty six. So that is the
formula. Seven forty six is the actual

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wattage for one horse power. Okay, so it's horsepower times seven forty six

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divided by the vaults times the efficiency
times the power factor. Well, remember

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what I said, you want to
work the multiplications out first, So work

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the top out and work the bottom
out. So let's worked the top.

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So we said it was a half
horse power, right, so you take

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the one divided into two. That
gives you point five. If you look

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at it and you know that half
a horse power is point five, whereas

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one horse power is one point zero. Okay, you should know that,

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I hope, So point five is
our horsepower. So we're going to do

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point five times seven forty six and
that gives me three seventy three. So

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that's the top part of this equation. Now the bottom part was the voltage

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times of power factor. And remember
we want to convert everything into decimal So

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we started the right side of the
percentage and move two decimal spaces to the

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left, so that means that ninety
two percent ends up being point ninety two,

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and then the eighty percent same thing. Start from the right, move

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two spaces to the left. Now
that is point eight zero. Now let's

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do the multiplication. So one hundred
and fifteen times point ninety two times point

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eight zero, and that is eighty
four point sixty four. So now all

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you do is divide the top three
seventy three into the bottom eighty four point

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sixty four and I'm going to do
that now eighty four point sixty four,

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and that gives me four point four
amps. So that is my answer when

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the horse power is unknown, but
we do know what the horse power is,

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okay. Okay, So that was
that was easy, right, So

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that's when the horse power is actually
known, means you know what the horse

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power is. I don't know if
I said you don't know it, but

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you actually know what the horse power
is. Okay. So the next one

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is, okay, well, what
happens if how do I find the amps?

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If I the kilowatts are actually known, so I happen to know what

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the question gives me kilowatts? Okay, same concept here there's no motor,

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so we don't worry about the efficiency. So here it's saying, okay,

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let's look at this question. It
says I have a two hundred and thirty

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volt single phase circuit which has a
twelve kW power load, whatever that may

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be, and it operates at eighty
four percent power factor. Determine the current?

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Okay. So that's kind of a
question that you may get on an

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exam. So how do I determine
what the current is based on the fact

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that I'm giving the voltage, I'm
giving the kilowatts, and I've given the

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power factor. Well, this formula
is very similar to what we did with

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the previous one when we knew what
the horsepower was. This is a little

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different though, since there's no horsepower
involved. We don't equate the seven forty

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six. That has no play here. So now it's just killowatts times a

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thousand divided by volts times the power
factor. Okay, so we know that

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it is twelve kilowatts, so we
could skip one here and just go we

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know that twelve kilowatts the k is
Kei low, so we know that it's

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twelve thousand watts. Okay, you
could skip that one, but if you

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didn't, you just go twelve times
one thousand, So that's twelve. And

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then on the bottom part it's the
voltage times of power factor. Well,

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we said it was eighty four percent
power factors. Start from the right of

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the four, move two spaces to
the left. Point eight fours now are

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00:15:28,159 --> 00:15:33,039
our multiplier, So we do two
thirty. Remember, use the voltage they

206
00:15:33,080 --> 00:15:37,480
give you times point eight four,
and that is one hundred and ninety three

207
00:15:37,519 --> 00:15:41,559
point two. Now that we have
it figured out. We do the twelve

208
00:15:41,639 --> 00:15:46,559
thousand divided by the one ninety three
point two, So it's twelve thousand divided

209
00:15:46,559 --> 00:15:50,919
by the one ninety three point two, and that's going to give me sixty

210
00:15:50,960 --> 00:15:54,440
two point one one. Remember that
we can drop anything that is what under

211
00:15:54,559 --> 00:15:58,840
point five, So this is point
one one, so we drop it.

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00:15:58,919 --> 00:16:03,279
So the amps is six sixty two
amps. So that's what our amp is

213
00:16:03,320 --> 00:16:08,320
for that twelve kW power load right
at two thirty volts with an eighty four

214
00:16:08,360 --> 00:16:14,279
percent power factor. Okay. Now, again, these are just questions you

215
00:16:14,360 --> 00:16:17,159
may get on an exam and you're
sitting there going, okay, I don't

216
00:16:17,200 --> 00:16:18,399
know how to work the power factor. I don't know how to work the

217
00:16:18,440 --> 00:16:23,440
efficiency. And that's that's why we're
doing this. This that's what this episode,

218
00:16:23,440 --> 00:16:26,759
this podcast is all about, because
I do get a fair enough questions

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00:16:27,559 --> 00:16:33,919
that people ask about that. Okay, all right, Well, so this

220
00:16:34,080 --> 00:16:37,919
next one is one that says,
Okay, let's assume we give you a

221
00:16:38,000 --> 00:16:42,600
question and we actually know what the
kVA is or the kill of volt ampiers.

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00:16:42,960 --> 00:16:48,159
Okay, so in this question,
it's one hundred and fifteen volt circuit.

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00:16:48,279 --> 00:16:53,200
It's a two kVA or y'all know
k mean two thousand va. Vault

224
00:16:53,240 --> 00:17:02,639
ampires single phase generator operating at full
load will deliver how many amps? Okay,

225
00:17:02,919 --> 00:17:06,480
how do you determine this one?
Well, in this formula it is

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00:17:06,640 --> 00:17:11,880
k it's the kVA or the killer
vault Dampier's times a thousand, So that

227
00:17:11,920 --> 00:17:15,000
would you know, you'd be two
times a thousand because it's two kVA,

228
00:17:15,279 --> 00:17:19,160
or as you as we said before, if you know already that two k

229
00:17:19,680 --> 00:17:23,839
va equates to two thousand va,
then you can skip that little math,

230
00:17:25,319 --> 00:17:29,880
and so the top part would be
two thousand and again, the bottom part

231
00:17:30,279 --> 00:17:33,039
is the voltage, which is one
fifteen. So this is going to be

232
00:17:33,920 --> 00:17:38,279
two times one thousand divided by one
fifteen, or in our case, two

233
00:17:38,319 --> 00:17:45,480
thousand divided by one fifteen, and
that equals seventeen point four amps. So

234
00:17:45,559 --> 00:17:48,960
you just take two thousand, you
can divide that by one fifteen, and

235
00:17:48,000 --> 00:17:52,799
you'll get seventeen point three nine one
three. Obviously in this case three nine,

236
00:17:53,160 --> 00:17:57,319
you can work it up to seventeen
point four and you're rounding it up.

237
00:17:57,759 --> 00:18:03,000
Okay, that's so that is okay, all right, So and we're

238
00:18:03,000 --> 00:18:06,319
working this. When we work this
to the all the way down to the

239
00:18:06,359 --> 00:18:11,880
simplest form. Okay. Now,
remember ampier is the rate of flow of

240
00:18:12,000 --> 00:18:15,599
currents. So this is again full
load. We told you that it was

241
00:18:15,640 --> 00:18:19,599
a full load being delivered, and
that full load on that one hundred and

242
00:18:19,599 --> 00:18:25,240
fifty volt two kVA. We didn't
work anything, We didn't drop. It

243
00:18:25,400 --> 00:18:29,119
is full load, full being drawn. That full two kVA is being drawn.

244
00:18:29,440 --> 00:18:34,359
That would be again seventeen point four
amps. Okay. So now up

245
00:18:34,359 --> 00:18:38,440
to this point, all of these
that we've done have been pretty straightforward.

246
00:18:38,799 --> 00:18:44,160
But if you remember something, every
one of these is dealing with single phase.

247
00:18:45,200 --> 00:18:49,519
So what do we do differently if
we're dealing with three phase? Well,

248
00:18:49,559 --> 00:18:56,000
the only difference, folks, is
that you're going to be throwing in

249
00:18:56,039 --> 00:18:59,319
the value of one point seventy three
to two, which is a square root

250
00:18:59,359 --> 00:19:03,319
of three, okay, when we're
doing three phase, because there's three legs

251
00:19:03,480 --> 00:19:07,279
square root of three. Okay.
So if we know the watts the voltage

252
00:19:07,279 --> 00:19:14,200
in the power factor are known,
then that equation is I equals p which

253
00:19:14,240 --> 00:19:18,640
is the watts divided by E times
PF, which is power factor times one

254
00:19:18,680 --> 00:19:25,400
point seventy three. Okay. So
in this case, the only differing variable.

255
00:19:25,400 --> 00:19:29,119
It's still a fifteen hundred watt load. The power factor is still eighty

256
00:19:29,160 --> 00:19:30,920
six percent. Y'all know how to
convert that to point eighty six. Right,

257
00:19:32,039 --> 00:19:33,720
start at the right of the six
two decimal spots to the left.

258
00:19:34,200 --> 00:19:38,680
You get it, and it's a
three phase load with two hundred and thirty

259
00:19:38,880 --> 00:19:44,359
vault source. Okay. So in
this one is fairly simple the same way

260
00:19:44,400 --> 00:19:48,480
we did before. The p here
is fifteen hundred watts, the e is

261
00:19:48,519 --> 00:19:52,079
two thirty, the power factor is
point eighty six. Remember eighty six percent

262
00:19:52,119 --> 00:19:56,759
converted to decimal and then times one
point seventy three, which is the square

263
00:19:56,799 --> 00:20:00,160
root of three, because it is
a three phase. So in this case,

264
00:20:00,200 --> 00:20:07,200
it would be fifteen hundred divided by
two thirty times point eight six times

265
00:20:07,359 --> 00:20:12,000
one point seventy three two. That
is three hundred and forty two. Okay,

266
00:20:12,359 --> 00:20:15,240
And hold, let me go in
and let me work this all the

267
00:20:15,279 --> 00:20:21,319
way out. Two thirty times point
eighty six times one point seven three two

268
00:20:22,799 --> 00:20:27,160
is going to be three forty two
point five, okay, And so we'll

269
00:20:27,200 --> 00:20:30,519
just say at three foot two five. Now, one of the things we

270
00:20:30,559 --> 00:20:36,000
do at that point is take the
fifteen hundred and divided by three forty two

271
00:20:36,000 --> 00:20:40,680
point five, and that's going to
give me four point three seven, which

272
00:20:40,720 --> 00:20:42,720
I can round to full point four, and that's going to give me four

273
00:20:42,759 --> 00:20:49,720
point four amps. Okay, Now
what if same thing? Now what if

274
00:20:49,759 --> 00:20:55,480
we have the same equation and they
give you the horse power and they want

275
00:20:55,480 --> 00:20:57,319
to know what the AMPS is on
this three phase Again, it's just like

276
00:20:57,400 --> 00:21:00,559
what we did in single phase.
The only difference is we're adding that one

277
00:21:00,599 --> 00:21:06,680
point seventy three to two to the
lower portion, or the denominator portion of

278
00:21:06,720 --> 00:21:11,000
the equation. Okay, remember when
I say that though, folks to people

279
00:21:11,119 --> 00:21:17,319
not to get confused when I talk
denominators and numerators and stuff like that,

280
00:21:17,319 --> 00:21:22,640
that you know the difference that the
denominator is the bottom part, the numerator

281
00:21:22,720 --> 00:21:26,319
is the top part. So we're
talking the denominator here is the bottom part.

282
00:21:26,519 --> 00:21:29,200
Okay. So how do we do
this one? So same scenario.

283
00:21:30,119 --> 00:21:32,440
We have to know what the horsepower
is. So let's read the question.

284
00:21:33,160 --> 00:21:40,240
Determine the AMP load of this three
phase half horse power two thirty volt motor.

285
00:21:40,880 --> 00:21:44,680
The motor has an efficiency rating of
ninety two percent, and this is

286
00:21:44,799 --> 00:21:47,000
very much going to be in line
with the nameplate, by the way,

287
00:21:47,440 --> 00:21:51,079
and the power factor of eighty percent. Okay, Well, the first thing

288
00:21:51,119 --> 00:21:56,039
I like to do is convert all
of these percentages into decimals, so that

289
00:21:56,160 --> 00:22:00,519
ninety two percent becomes a point nine
to two, that eighty percent a point

290
00:22:00,519 --> 00:22:04,200
eight zero, right. And so
now since we have the same half horse

291
00:22:04,200 --> 00:22:07,160
power, I'm gonna vide the one
into the two. That's how I get

292
00:22:07,160 --> 00:22:10,400
the point five. Although you probably
know a half of one horse power is

293
00:22:10,440 --> 00:22:14,400
point five, I'm just kind of
talking through it for you. So I'm

294
00:22:14,400 --> 00:22:19,400
gonna haveo point five times seven forty
six, and so the top part is

295
00:22:19,440 --> 00:22:23,400
gonna be three seventy three. Okay, that's the numerator portion, and then

296
00:22:23,440 --> 00:22:29,119
the bottom part I've got to do
the math. So two thirty times point

297
00:22:29,200 --> 00:22:36,759
ninety two times point eight zero times
one point seventy three two is two point

298
00:22:37,160 --> 00:22:41,039
two nine three point one. So
I can just take the two nine three

299
00:22:41,119 --> 00:22:44,839
and drop the other. So now
I just take the three seventy three,

300
00:22:45,480 --> 00:22:49,000
divide that into the two ninety three, and that gives me one point two

301
00:22:49,000 --> 00:22:55,920
seven ampires. Okay, so that
motor and that's probably gonna be more in

302
00:22:56,000 --> 00:23:00,519
line with a name plate Okay,
not the same as the FLC, which

303
00:23:00,519 --> 00:23:03,480
we're going to use for sizing circuits
and a short circuit ground for protection,

304
00:23:03,559 --> 00:23:07,440
because the code tells us too.
Right. This is kind of if you

305
00:23:07,480 --> 00:23:11,599
happen to get a question that's asking
you to calculate this out, this is

306
00:23:11,599 --> 00:23:17,480
how you would do it. Okay, makes sense. Okay, let's keep

307
00:23:17,519 --> 00:23:19,359
going and kind of finish these out. So what if I have a three

308
00:23:19,400 --> 00:23:23,920
phase and I actually know what the
kilowats are? So the only thing that

309
00:23:23,920 --> 00:23:27,519
you're changing with versus what you did
with the single phase is that one point

310
00:23:27,559 --> 00:23:32,160
seventy three to two. So if
I know what the kilowats are, what's

311
00:23:32,200 --> 00:23:36,240
the question? Okay, it's two
hundred and thirty VOO three phase circuit now

312
00:23:36,640 --> 00:23:41,440
with a twelve kW power load that
operates at eighty four percent power factor,

313
00:23:41,000 --> 00:23:45,920
determine the current Okay, simple question. I'm going to say, Okay,

314
00:23:45,960 --> 00:23:48,440
well, I can skip one step
of doing the kW times one thousand,

315
00:23:48,440 --> 00:23:52,680
because I think we all know that
twelve kW is twelve thousand watts, so

316
00:23:52,720 --> 00:23:55,920
I can skip that math. So
that's going to be the numerator. That's

317
00:23:55,960 --> 00:24:00,599
the top part. The bottom part
is the E time PF times one point

318
00:24:00,599 --> 00:24:04,359
seven three two, So we know
that it is two thirty and I'm gonna

319
00:24:04,359 --> 00:24:08,599
work the math two thirty times,
and we turned our eighty four percent into

320
00:24:08,680 --> 00:24:14,799
a decimal point eight four, so
times point eight four times. And then

321
00:24:14,839 --> 00:24:18,359
of course the one seven three,
which is a square root of three times

322
00:24:18,359 --> 00:24:22,400
one point seven four. Excuse me, one point seven three, So I

323
00:24:22,440 --> 00:24:25,039
don't know where I was getting that
from. All right, times point eight

324
00:24:25,119 --> 00:24:30,119
four times one point seven three,
which equals three hundred and thirty four point

325
00:24:30,200 --> 00:24:34,319
two three. Okay, So it's
two three six, So we're gonna round

326
00:24:34,319 --> 00:24:38,759
this to three thirty four point two
four, all right. So then you

327
00:24:38,880 --> 00:24:42,240
just take the twelve thousand, which
is in the numerator's position, divided by

328
00:24:42,440 --> 00:24:48,559
three thirty four point two four,
and that gives me a total of thirty

329
00:24:48,599 --> 00:24:52,240
five point nine zero. So we're
gonna round this to thirty six ampiers.

330
00:24:52,400 --> 00:24:56,839
Okay, So the answer here is
thirty six amps. Okay, so that's

331
00:24:56,880 --> 00:25:00,440
what the ampload is, uh for
the cur draw is for this motor at

332
00:25:00,480 --> 00:25:06,640
this power factor. And then lastly, well, well we'll end this out

333
00:25:07,279 --> 00:25:11,319
on this episode with if you know
the kill of old amp here, and

334
00:25:11,440 --> 00:25:15,759
you guessed it. It's essentially the
same as we did before, except for

335
00:25:15,039 --> 00:25:18,279
the top part is the kill of
volt ampier times a thousand. Well,

336
00:25:18,319 --> 00:25:22,440
I think we all know that if
it's like a four kVA, then that's

337
00:25:22,440 --> 00:25:25,240
four thousand, so you can save
a little step there. But if you

338
00:25:25,279 --> 00:25:27,200
didn't know, then you take the
kill of old ampire, which if it

339
00:25:27,279 --> 00:25:30,200
was four kill of old ampiers,
you do four times one thousand, four

340
00:25:30,240 --> 00:25:34,680
thousand. So what's the question?
A two hundred and thirty volt four kVA

341
00:25:34,880 --> 00:25:41,279
three phase generator operating at full load
would deliver blank amps. Okay, how

342
00:25:41,279 --> 00:25:45,599
do we prove it? Okay,
Well, the equation is kill of old

343
00:25:45,599 --> 00:25:48,920
ampires times a thousand divided by e
times one point seventy three to two.

344
00:25:49,519 --> 00:25:52,720
Well, we know the kkva was
four, so four times a thousand,

345
00:25:52,799 --> 00:25:57,599
so the top numerator is four thousand, and then the bottom is going to

346
00:25:57,640 --> 00:26:04,240
be two thirty times one point seven
three, and that is gonna give us

347
00:26:06,119 --> 00:26:08,839
three nine seven. Now, by
the way, if you wanted to go

348
00:26:08,880 --> 00:26:12,279
all the way out at one point
seven three two, you could, okay,

349
00:26:12,319 --> 00:26:17,640
but you're gonna get roughly the same
values as using one point seven three.

350
00:26:18,039 --> 00:26:19,359
But if you want to work it
all the way out. That's fine.

351
00:26:19,480 --> 00:26:22,519
If you want all of the square
root of three, that's fine.

352
00:26:22,599 --> 00:26:26,680
I'll show you the difference if you
want to see it. For somebody out

353
00:26:26,720 --> 00:26:29,359
there, I know this hollering saying, Paul, it's not one point seven

354
00:26:29,400 --> 00:26:33,039
three, it's one point seven three
to two, okay, whatever, I'll

355
00:26:33,079 --> 00:26:38,039
do both for you. So in
this case would be two thirty. We're

356
00:26:38,039 --> 00:26:44,480
doing the denominator portion two thirty times
one point seven three, and that is

357
00:26:44,519 --> 00:26:48,279
three three ninety seven point nine.
So I'm gonna take the four thousand.

358
00:26:48,640 --> 00:26:52,960
I'm going to divide that into three
ninety seven point nine, and that gives

359
00:26:53,000 --> 00:26:57,640
me ten point zero five ams,
so it's ten ams. But okay,

360
00:26:57,680 --> 00:27:00,920
Paul, Paul, you need to
use the one point seven three two,

361
00:27:00,920 --> 00:27:04,640
okay, okay. So I'm gonna
go two thirty times one point seven three

362
00:27:04,759 --> 00:27:10,000
two, and that gives me three
ninety eight point three six. Okay,

363
00:27:10,119 --> 00:27:15,119
So three ninety eight point three six
is my value. I would just use

364
00:27:15,160 --> 00:27:18,759
three ninety eight. Drop the point
three six, so I would go four

365
00:27:18,839 --> 00:27:23,720
thousand divided by three ninety eight,
and that gives me ten point zero five.

366
00:27:25,000 --> 00:27:26,759
Still drop the point zero five,
so it's still ten amps, folks,

367
00:27:26,759 --> 00:27:30,319
it's not gonna make a difference.
But if you want to use one

368
00:27:30,319 --> 00:27:33,400
point seventy three to two all the
way out, go for it. Now.

369
00:27:33,440 --> 00:27:37,119
You can do that if you like. Don't make us complicated, please,

370
00:27:37,599 --> 00:27:41,200
it's not it's not worth making it
complicated, all right. So that's

371
00:27:41,240 --> 00:27:45,759
how you find the amps, whether
it's single phase, whether it's three phase,

372
00:27:47,359 --> 00:27:51,200
and you ask these kind of questions
where they give you the kilowatts,

373
00:27:51,359 --> 00:27:55,000
or they give you the killer vault
damp years, or they give you the

374
00:27:55,039 --> 00:27:59,000
watts the vaults and the power factor, or maybe when the horse power is

375
00:27:59,119 --> 00:28:03,079
known, they give you all these
other variables. These are ways that you

376
00:28:03,119 --> 00:28:07,400
can answer these questions to find the
ampage. Okay. So that's the whole

377
00:28:07,400 --> 00:28:11,519
purpose of this episode was called finding
the amps based on the questions. And

378
00:28:11,680 --> 00:28:17,559
obviously normal OHMS law is pretty simple, right you have the E R Okay,

379
00:28:17,880 --> 00:28:21,480
so E the voltage divided by are
the resistance will give you the current

380
00:28:22,000 --> 00:28:26,960
right, which is I. But
here is just a little more complex when

381
00:28:26,000 --> 00:28:30,599
we're trying to find the amperage values
based on whether it's watt's volts and kind

382
00:28:30,599 --> 00:28:37,000
of throw in the power factor scenario
in or things like that because people ask

383
00:28:37,079 --> 00:28:41,359
about that. And also it was
important to talk earlier about the horsepower for

384
00:28:41,440 --> 00:28:47,119
single phase versus three phase, just
so you have kind of an understanding on

385
00:28:47,160 --> 00:28:49,119
how this all works. Okay,
all right, folks, hopefully you got

386
00:28:49,160 --> 00:28:52,519
something out of this episode. Again, we're just talking amps, and that

387
00:28:52,680 --> 00:28:57,039
was it, And maybe we'll have
another episode and I'll talk about maybe how

388
00:28:57,079 --> 00:29:00,680
to find horsepower, how to find
wattage or whatever. If that's what you

389
00:29:00,759 --> 00:29:04,920
want, we more certainly can do
that until next time, folks, Stay

390
00:29:06,000 --> 00:29:18,880
safe, God bless and we'll catch
you on another episode
